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How many different signals can be sent up on a flagpole if each signal requires 3 (three) blue and 3 (three) yellow flags
and the flags are identical except for color?
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You have 6 positions, in all : (3+3 = 6).
Of these 6 positions, you can select 3, where you will place 3 blue flags, by
ways =
= 20 ways.
After that, you just HAVE NO choice where to put yellow flags:
you have only one opportunity to place them in three places that remained free.
Hence, you have 20 ways and may expose exactly 20 signals, under the given conditions.
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It can be solved by different way, using the formula for permutations in sets containing indistinguishable element.
We have the set of 6 elements, of which the group of 3 elements are indistinguishable
and another group of 3 elements are indistinguishable.
The number of all distinguishable arrangements (permutations) of such set is
=
= 20,
the same answer.
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See the lesson
- Arranging elements of sets containing indistinguishable elements
in this site.