SOLUTION: Ten sets of twins (20 people) are applying for 3 committee positions. If no sets of twins are allowed on a committee, how many ways can the committee be chosen?

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Question 1117956: Ten sets of twins (20 people) are applying for 3 committee positions. If no sets of twins are
allowed on a committee, how many ways can the committee be chosen?

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
The members of the committee go from different twin sets.


So, there are  C%5B10%5D%5E3 choices between the sets of twins, and then 2*2*2 choices inside each twin set.


The total number of ways is  C%5B10%5D%5E3%2A8 = %28%2810%2A9%2A9%29%2F%281%2A2%2A3%29%29%2A8 = 1080.