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A test has 6 multiple choice questions each having 4 possible answers. In how many ways can a student respond to the questions if:
a) All questions must be answered? <<<---=== Answer.
ways.
Solution
For simplicity, let us assume that you write one of the 4 letters A, B, C or D as the possible answer to each question.
Then you have 4 opportunities for each of 6 question, which gives the above answer.
Memorize: the space of events in this case is the space of all 6-letter words written in 4-letter alphabet.
b) Not all questions must be answered? <<<---=== Answer.
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Solution
We can very easily reduce this problem to the previous scheme by making an agreement that we write the fifth symbol/letter "E"
where the question is unanswered.
Then the space of events is the space of all 6-letter words written in 5-letter alphabet, which gives the above answer.
Solved.
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The space (the set) of n-symbol words over the m-symbol alphabet is the third entity widely used in Combinatorics after Permutations and Combinations.