SOLUTION: Prove that C(k,k)=1 for any value of k.

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Question 1115388: Prove that C(k,k)=1 for any value of k.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
C(n,k) = +n%21%2F%28%28n-k%29%21%28k%21%29%29+

C(k,k) = +k%21%2F%28%28k-k%29%21%28k%21%29%29++=++k%21%2F%280%21%2Ak%21%29+=+1+