SOLUTION: A bookseller has 10 identical books of math 101, 3 identical books of Acc 201, and 5 identical books of Stat 102. In how many different ways can he display his books?(Note that the

Algebra ->  Permutations -> SOLUTION: A bookseller has 10 identical books of math 101, 3 identical books of Acc 201, and 5 identical books of Stat 102. In how many different ways can he display his books?(Note that the      Log On


   

Question 1114945: A bookseller has 10 identical books of math 101, 3 identical books of Acc 201, and 5 identical books of Stat 102. In how many different ways can he display his books?(Note that the books in same subject are identical, one cannot be differed from others)

Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
In  %2810%2B3%2B5%29%21%2F%2810%21%2A3%21%2A5%21%29  ways.


The numerator is the total number of permutations of 10+3+5 = 18 objects.


Each factorial in the denominator reflects the fact the inside the corresponding group of books their permutations produce indistinguishable arrangements.


Now it is your part of work to compute this number.