SOLUTION: A bus starts with 6 people and stops at 10 different stops, how many different ways can the 6 people depart if any passenger can depart at any bus stop

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Question 1108155: A bus starts with 6 people and stops at 10 different stops, how many different ways can the 6 people depart if any passenger can depart at any bus stop

Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
1-st person can go out at any of 10 bus stops - 10 opportunities.
2-nd person can go out at any of 10 bus stops - 10 independent opportunities.
3-rd person can go out at any of 10 bus stops - 10 independent opportunities.
4-th person can go out at any of 10 bus stops - 10 independent opportunities.
5-th person can go out at any of 10 bus stops - 10 independent opportunities.
6-th person can go out at any of 10 bus stops - 10 independent opportunities.


In all, there are  10%5E6 different ways.


Same number of ways as how many 6-letter words do exist comprising of 10 given letters (symbols) of the alphabet, if letters repetition is allowed.


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I just solved it at least two times in this forum.

See the lesson
    - Combinatoric problems for entities other than permutations and combinations
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.