SOLUTION: In a cooking competition, 6 out of 10 contestants are females. In how many ways can one choose the champion, first and second runners-up?

Algebra ->  Permutations -> SOLUTION: In a cooking competition, 6 out of 10 contestants are females. In how many ways can one choose the champion, first and second runners-up?       Log On


   



Question 1105866: In a cooking competition, 6 out of 10 contestants are females. In how many ways can one choose the champion, first and second runners-up?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
In a cooking competition, 6 out of 10 contestants are females. In how many ways can one choose the champion, first and second runners-up?
----------------
10*9*8 = 720 ways