SOLUTION: Help me please!
A bus starts with 6 people and stops at 10 different stops. How many different ways can the 6 people depart if;
A. Any passenger can depart at any bus stop.
Algebra ->
Permutations
-> SOLUTION: Help me please!
A bus starts with 6 people and stops at 10 different stops. How many different ways can the 6 people depart if;
A. Any passenger can depart at any bus stop.
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A bus starts with 6 people and stops at 10 different stops. How many different ways can the 6 people depart if;
A. Any passenger can depart at any bus stop.
B. No two passengers can depart at the same bus stop. Answer by ikleyn(52778) (Show Source):
It is the same as to ask:
In how many ways 6 different pigeons can be placed in 10 pigeonholes, under the condition
that there are no two pigeons in one pigeonhole ?
The answer is: in 10*9*8*7*6*5 = 151200 ways.
1-st pigeon can be placed into any of 10 pigeonholes;
2-nd pigeon can be placed into any of remained 9 pigeonholes;
3-rd pigeon can be placed into any of remained 8 pigeonholes;
4-th pigeon can be placed into any of remained 7 pigeonholes;
5-th pigeon can be placed into any of remained 6 pigeonholes;
6-th pigeon can be placed into any of remained 5 pigeonholes.
