SOLUTION: 10Cr=20C(r+1)

Algebra ->  Permutations -> SOLUTION: 10Cr=20C(r+1)      Log On


   



Question 1102983: 10Cr=20C(r+1)
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
10Cr=20C(r+1)
==============================
This is an old one… and has no solution.
+10Cr++%3C%3E+20C%28r%2B1%29+ for all values of r.
There are only 11 values to check (after the first 6 it is pretty obvious
they can never be equal, but all 11 values are listed for completeness):
+10C0+=+1++%3C%3E+20C1+=+20+
+10C1+=+10+%3C%3E+20C2+=+190+
+10C2+=+45+%3C%3E+20C3+=+1140+
+10C3+=+120+%3C%3E+20C4+=+4845+
+10C4+=+210+%3C%3E+20C5+=+15504+
+10C5+=+252+%3C%3E+20C6+=+38760+
+10C6+=+210+%3C%3E+20C7+=+77520+
+10C7+=+120+%3C%3E+20C8+=+125970+
+10C8+=+45+%3C%3E+20C9+=+167960+
+10C9+=+10+%3C%3E+20C10+=+184756+
+10C10+=+1+%3C%3E+20C11+=+167960+