SOLUTION: in how ways can 5 boys and 3 girls be arranged in a circle if the girl must stand together

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Question 1102191: in how ways can 5 boys and 3 girls be arranged in a circle if the girl must stand together


Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


If the 5 girls are together, then the 3 boys are also together.

The number of ways of arranging the 5 girls is 5!=120; the number of ways of arranging the 3 boys is 3!=6.

Since the 8 people are arranged in a circle, you don't know "where the starting point is"; it could be with any one of the 8 people.

So the total number of arrangements is
%28120%2A6%29%2F8+=+90

(Try to get other answers; I often analyze this kind of problem incorrectly.)

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
I want to make a couple of notices to the solution by @greenestamps.

1.  In his text he mixed the number of boys and girls.

    The problem talks about 3 girls and 5 boys.

    But in his logic it does not affect his results.



2.  The second notice is more serious.


    I will use another logic and will get another answer.

    Since the team of boys and girls is arranged in a circle, we can think that the girls go first ("women first") 
    and we arrange and count our circular permutations starting from the girls.


    We can start counting (arranging) from any of the 3 girls, arranging them in 3! = 6 ways.

    Then we arrange 5 boys by 5! = 120 ways (120 permutations for 5 objects).


    That's all.  In all we have 6*120 = 720 circular arrangements.

    There is no need to divide 720 by 8, because we just accounted for the circular symmetry, when started our arrangements from the girls.

So, my answer is 6*120 = 720 ways/(circular arrangements).