Question 1088182: In a box , there are 3 red marbles,4 green marbles and 5 yellow marbles.in how many ways can you draw three marbles if 1 they are of the same color
2)they are of 3 different colors?
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website! I'm pretty sure this was answered already, but here it is again.
1. Order doesn't matter so we use the combination formula C(n,k) = n!/((n-k)!k!). The outcomes in this case are also mutually exclusive, so we simply add them:
C(3,3) + C(4,3) + C(5,3) = 1 + 4 + (5*4/2) = 15
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2. Order doesn't matter, so another combination scenario. Use counting principle (independent events multiply the number of possible outcomes):
C(3,1)*C(4,1)*C(5,1) = 3*4*5 = 60
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