Question 1085739: In a special movie club, you have a choice of watching any 3 movies out of 45 possibilities each month. How many different ways can you choose the 3 movies?
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! You have 3 movies, A B and C. You don't care if you watch C first, or B, or A, or which you watch next and so on.
So we are dealing with a Combination, where the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed
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C(n, r) = n!/(r!(n-r)!)
C(45, 3) = 45!/(3!(45-3)!) = 14,190 ways
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