SOLUTION: From 5 physicists, 4 chemists and 3 mathematicians a committee of 6 is to be chosen so as to include 3 physicists, 2 chemists and 1 mathematician in how many ways can this be done?

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Question 1083751: From 5 physicists, 4 chemists and 3 mathematicians a committee of 6 is to be chosen so as to include 3 physicists, 2 chemists and 1 mathematician in how many ways can this be done?
Found 2 solutions by josmiceli, muthbab@gmail.com:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
C( 5,3 ) + C( 4,2 ) + C( 3, 1 )
+5%21%2F%28+3%21%2A2%21+%29+%2B+4%21%2F%28+2%21%2A2%21+%29+%2B+3%21%2F%28+1%21%2A2%21+%29+
+%285%2A4%29+%2F+2+%2B+%284%2A3%29+%2F+2+%2B+3+
+10+%2B+6+%2B+3++=+19+
There are 19 ways to choose 3 physicists,
2 chemists, and 1 mathematician

Answer by muthbab@gmail.com(5) About Me  (Show Source):
You can put this solution on YOUR website!
You will select 3 physicists out of 5: i.e C(5,3) = 10 different ways
Then select 2 chemists out of 4: i.e, C(4,2) = 6 different ways
Lastly, one position will be filled by 1 out of 3 mathematicians, i.e 3
That is 10X6X3 = 180
But note: The question omitted a crucial word 'Different' in "....how many DIFFERENT ways can this be done"