You can put this solution on YOUR website! The P's can have
C( 5,2 ) =
C( 5,2 ) =
C( 5,2 ) =
C( 5,2 ) = combinations
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For each of these combinations, there are
P( 3,3 ) =
P( 3,3 ) = permutations
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C( 5,2 ) * P( 3,3 ) =
There are 60 different ways
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Definitely get a 2nd opinion on this