SOLUTION: if 4 Americans, 3 French men and 3 Ethiopians are to be seated in a row , how many seating arrangements are possible when people of the same nationality must sit next to each other

Algebra ->  Permutations -> SOLUTION: if 4 Americans, 3 French men and 3 Ethiopians are to be seated in a row , how many seating arrangements are possible when people of the same nationality must sit next to each other      Log On


   

Question 1080711: if 4 Americans, 3 French men and 3 Ethiopians are to be seated in a row , how many seating arrangements are possible when people of the same nationality must sit next to each other ?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The permutations for each nationality
have all possible arrangements in the row
I'll say:
+A+=+4%21+
+F+=+3%21+
+E+=+3%21+
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All possible arrangements of A,F,and E are +3%21+
+3%21%2A4%21%2A3%21%2A3%21+=+6%2A24%2A6%2A6+
+6%2A24%2A6%2A6+=+5184+
There are 5,184 possible arrangements
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Definitely get another opinion on this