SOLUTION: You can answer any 20 questions from the 24 questions on an exam. In how many different ways can you choose the 20 questions, assuming that the order in which you choose the questi

Algebra ->  Permutations -> SOLUTION: You can answer any 20 questions from the 24 questions on an exam. In how many different ways can you choose the 20 questions, assuming that the order in which you choose the questi      Log On


   

Question 1080015: You can answer any 20 questions from the 24 questions on an exam. In how many different ways can you choose the 20 questions, assuming that the order in which you choose the questions is irrelevant?
(If necessary, consult a list of formulas.)

Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
The relevant notion/comception in Math is called "combinations".

On combinations, see the lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
in this site.

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".


The answer to your question is: your number is C%5B24%5D%5E20 = %2824%2A23%2A22%2A21%29%2F%281%2A2%2A3%2A4%29 = 10626.


Happy learning !!