SOLUTION: If I have a list of numbers 0-9 and I have a 4 digit code how many possible solutions are there

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Question 1055991: If I have a list of numbers 0-9 and I have a 4 digit code how many possible solutions are there
Found 3 solutions by addingup, ikleyn, MathTherapy:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
0-9 is 10 numbers. Your code is 4 digits:
10C4 = n!/(n-k)! = 10!/(10-4)! = 5,040 possible combinations

Answer by ikleyn(52946) About Me  (Show Source):
You can put this solution on YOUR website!
.
If no restrictions on repetition of digits, and
if no restriction of the type "0 can not go first" . . .

then the number of codes is 10%5E4.

If there are restrictions, they MUST be listed in the condition.

Since we do not see any restrictions in the condition, they do not exist in this problem.


Answer by MathTherapy(10560) About Me  (Show Source):
You can put this solution on YOUR website!
If I have a list of numbers 0-9 and I have a 4 digit code how many possible solutions are there
If 0000 is one, then each of the 4 digits can be chosen from any of the 10 (0 - 9) digits, so possible 4-digit codes total: