SOLUTION: Two freshmen, 2 sophomores, 2 juniors, and 3 seniors are on a panel. In how many ways can the panelists be seated if each class must sit together?

Algebra ->  Permutations -> SOLUTION: Two freshmen, 2 sophomores, 2 juniors, and 3 seniors are on a panel. In how many ways can the panelists be seated if each class must sit together?      Log On


   



Question 1049797: Two freshmen, 2 sophomores, 2 juniors, and 3 seniors are on a panel. In how many ways can the panelists be seated if each class must sit together?
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.
4! is the number of permutations of four objects.

In your case the objects are "classes".

On permutations, see the lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Problems on Permutations
in this site.