SOLUTION: We want to select a committee of five members from a group of five women and six men. The order of selection is irrelevant. How many committees can we make consisting of two wo

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Question 1042354: We want to select a committee of five members from a group of five women and six men. The order of selection is irrelevant.
How many committees can we make consisting of two women and three men?
I have tried this several ways but I am doing something wrong. Can someone show me as I have more to do like this for my upcoming summer final.

Found 2 solutions by jorel555, chen.aavaz:
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
You have 5 women to choose from. 5 choose 2 is 5!/3!2!, which equals 10. Similarly, for men it's 6 choose 3, which is 20.
20 x 10=200 different ways of choosing 2 women and 3 men. ☺☺☺☺

Answer by chen.aavaz(62) About Me  (Show Source):
You can put this solution on YOUR website!
First we calculate how many committees of 2 women we can make out of the 5 women:
W+=+5%21%2F%285-2%29%212%21+=+10 hence we can have 10 such committees
Similarly, we calculate the number of committees of 3 out of 6 men:
M+=+6%21%2F%286-3%29%213%21+=+20
Now we must combine each of the first 10 women committees with each of the 20 men committees; thus the total number must be 10%2A20=200