Question 1037705: Mr. Parrish is making a seating chart for his 15 algebra 1 students. How many different seating charts can he make? (assuming there are only 15 seats) Is this permutation or combination?
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! You start with 15. Select a student and a chair. Now you have 14 to go. So you select another student and another chair. And you have 13 to go. And so on. How do you write this? This is how:
15! This means 15*14*13*12*11... etc, down to 1. Your calculator very likely has the ! key.
15! = 1,307,674,368,000 or in scientific notation: 1.307674368×10^12
|
|
|
