SOLUTION: Use binomial theorem to expand (x-2)^10 in ascending powers of x up to the terms containing x^3

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Question 1024008: Use binomial theorem to expand (x-2)^10 in ascending powers of x up to the
terms containing x^3

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Here are all 11 terms:

10C0%2A%28x%29%5E10%2A%28-2%29%5E0%22%22=%22%221%28x%5E10%29%2A1%22%22=%22%22x%5E10

10C1%2A%28x%29%5E9%2A%28-2%29%5E1%22%22=%22%2210%28x%5E9%29%2A%28-2%29%22%22=%22%22-20x%5E9

10C2%2A%28x%29%5E8%2A%28-2%29%5E2%22%22=%22%2245%28x%5E8%29%2A%284%29%22%22=%22%22180x%5E8

10C3%2A%28x%29%5E7%2A%28-2%29%5E3%22%22=%22%22120%28x%5E7%29%2A%28-8%29%22%22=%22%22-960x%5E7

10C4%2A%28x%29%5E6%2A%28-2%29%5E4%22%22=%22%22210%28x%5E6%29%2A%2816%29%22%22=%22%223360x%5E6

10C5%2A%28x%29%5E5%2A%28-2%29%5E5%22%22=%22%22252%28x%5E5%29%2A%28-32%29%22%22=%22%22-8064x%5E5

10C6%2A%28x%29%5E4%2A%28-2%29%5E6%22%22=%22%22210%28x%5E4%29%2A%2864%29%22%22=%22%2213440x%5E4

10C7%2A%28x%29%5E3%2A%28-2%29%5E7%22%22=%22%22120%28x%5E3%29%2A%28-128%29%22%22=%22%22-15360x%5E3

10C8%2A%28x%29%5E2%2A%28-2%29%5E8%22%22=%22%2245%28x%5E2%29%2A%28256%29%22%22=%22%2211520x%5E2

10C9%2A%28x%29%5E1%2A%28-2%29%5E9%22%22=%22%2210%28x%5E1%29%2A%28-512%29%22%22=%22%22-5120x

10C10%2A%28x%29%5E0%2A%28-2%29%5E10%22%22=%22%221%28x%5E0%29%2A%281024%29%22%22=%22%221024 

String them all together as a 10th degree polynomial, but you
only need to string the first 4 together.

Edwin