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There are 12C4 = 495 to select any 4 balls from the 12.
From that number, we must subtract
1. The number with no red balls:
That's 7C4 = 35 since there are 7 non-reds.
2. The number with exactly 1 red ball.
We can choose the 1 red ball 5C1 = 5 ways.
For each of those 5 ways to choose the 1 red ball,
there are 7C3 = 35 ways to choose the other 3 balls.
That's 5*35 = 175
Final answer: 495 - 35 - 175 = 285 ways
Edwin