SOLUTION: 2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party?
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Question 1012876: 2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party? Answer by ikleyn(52779) (Show Source):
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2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party?
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You can choose 3 boys of 6 for the first party by = = 20 ways.
You can choose 3 girls of 6 for the first party by = = 20 ways.
In total, you have 20*20 ways to choose 3 boys of 6 and 3 girls of 6 for the first party.
The rest of the boys and the girls will participate in the 2nd party without choice.
