Question 1008542: solve for n if P(n,3) = 24C(n,4)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve for n if P(n,3) = 24C(n,4)
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n!/(n-3)! = 24
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n(n-1)(n-2) = 24 * [n(n-1)(n-2)(n-3)/24]
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n(n-1)(n-2) = [n(n-1)(n-2)(n-3)]
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n-3 = 1
n = 4
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Checking::
P(4,3) = 24*C(4,4)
4!/1! = 24*1
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24 = 24
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cheers,
Stan H.
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