SOLUTION: The digits 5,6,7,8 and 9 are randomly arranged to form a three digit number. (digits are not repeated) Find the probability that the number is even and greater than 900.

Algebra ->  Permutations -> SOLUTION: The digits 5,6,7,8 and 9 are randomly arranged to form a three digit number. (digits are not repeated) Find the probability that the number is even and greater than 900.      Log On


   



Question 1008504: The digits 5,6,7,8 and 9 are randomly arranged to form a three digit number. (digits are not repeated) Find the probability that the number is even and greater than 900.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The number can start with either 5, 6, 7, 8, or 9 and all five are equally likely.
So the probability of starting with a 9 is,
P=1%2F5