SOLUTION: What formula do I use to solve for: A restaurant offers a dinner special that lets you choose from 10 entries, 8 side dishes, and 13 desserts. You can choose one entree, one side

Algebra ->  Permutations -> SOLUTION: What formula do I use to solve for: A restaurant offers a dinner special that lets you choose from 10 entries, 8 side dishes, and 13 desserts. You can choose one entree, one side       Log On


   



Question 1006419: What formula do I use to solve for: A restaurant offers a dinner special that lets you choose from 10 entries, 8 side dishes, and 13 desserts. You can choose one entree, one side dish and 2 deserts. How many different meals are possible? I tried 31!/1!*1!*2!= but got a weird number on the calculator. According to my textbook, the answer is supposed to be 6240, but I don't think I'm using the right formula. Could you please help?
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Answer shouldn't contain 31! in it. 31! is the number of ways to put all those dishes in some order.

You have 10 possible entrees to choose from, 8 possible side dishes to choose from. For desserts, you have 13C2 = 13!/(11!*2!) = 78 possible choices for deserts (please read on the binomial coefficient if you are unfamiliar).

Total # of ways is 10*8*78 = 6240