SOLUTION: Simplify the expression (3n+2)!/(3n-3)!
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Question 1001515
:
Simplify the expression
(3n+2)!/(3n-3)!
Answer by
Theo(13342)
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(3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)!
the (3n-3)! in the numerator and denominator cancel out and you are left with:
(3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)
for example:
let n = 7
3n+2 = 23
3n+1 = 22
3n+0 = 21
3n-1 = 20
3n-2 = 19
3n-3 = 18
(3n+2)! / (3n-3)! = (3n+2)*(3n+1)*(3n)*(3n-1)*(3n-2)*(3n-3)! divided by (3n-3)! which becomes:
23! / 18! = (23 * 22 * 21 * 20 * 19 * 18! divided by 18! which becomes:
(23 * 22 * 21 * 20 * 19)
the result is 4037880
i used my ti-84 to take 23! and divide it by 18! and i got 4037880.
this confirms the solution is correct.