SOLUTION: x is a number such that when (x+1)^2 is divided by (x-2), the quotient is 16 and the remainder is (x-3). What is the value of x? Thanks for your help!

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: x is a number such that when (x+1)^2 is divided by (x-2), the quotient is 16 and the remainder is (x-3). What is the value of x? Thanks for your help!      Log On


   

Question 999852: x is a number such that when (x+1)^2 is divided by (x-2), the quotient is 16 and the remainder is (x-3). What is the value of x?
Thanks for your help!
Found 2 solutions by mananth, dj8055:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

Dividend = divisor * quotient + remainder
%28x%2B1%29%5E2+=+%28x-2%29%2A16+%2B+%28x-3%29

x%5E2%2B2x+%2B1+=+16x-32%2Bx-3

x%5E2-15x%2B36=0

+x%5E2+-12x-3x%2B36=0

x(x-12)-3(x-12)=0
(x-12)(x-3)=0
x = 12 OR 3


Answer by dj8055(1) About Me  (Show Source):
You can put this solution on YOUR website!
(x+1)^2=(x-2)*16+(x-3)
(x+1)^2=16x-32+x-3
x^2+2x+1=17x-35
x^2-15x+36=0
x^2-12x-3x+36=0
x(x-12)-3(x-12)=0
(x-12)(x-3)=0
x=12 OR 3