SOLUTION: An equal number of boys and girls attended a birthday party. When 16 girls left, there were 5 times as many boys as girls. How many girls attended the birthday party at first?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: An equal number of boys and girls attended a birthday party. When 16 girls left, there were 5 times as many boys as girls. How many girls attended the birthday party at first?      Log On


   



Question 956199: An equal number of boys and girls attended a birthday party. When 16 girls left, there were 5 times as many boys as girls. How many girls attended the birthday party at first?
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An equal number of boys and girls attended a birthday party. When 16 girls left, there were 5 times as many boys as girls. How many girls attended the birthday party at first?
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Equations:
b = g
5(g-16) = b
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Substitute for "g" and solve for "b":
5(b-16) = b
5b - 80 = b
4b = 80
b = 20 (# of boys)
Ans: g = b = 20 (# of girls that attended at first)
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +b+ = number of boys and
+g+ = number of girls
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At the start,
+b+=+g+
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After +16+ girls leave,
+b+=+5%2A%28+g+-+16+%29+
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+b+=+5g+-+80+
+5g+-+b+=+80+
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Since +b+=+g+
+5b+-+b+=+80+
+4b+=+80+
+b+=+20+
and
+g+=+20+
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20 girls attended at first
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check:
+b+=+5%2A%28+g+-+16+%29+
+20+=+5%2A%28+20+-+16+%29+
+20+=+5%2A4+
+20+=+20+
OK