SOLUTION: for my outboard motor, the recommended ratio of gas to oil is 50:1 if my gas tank will hold 20L what percent of my mixture (gas & oil) is oil? and How much oil should i mix in m

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: for my outboard motor, the recommended ratio of gas to oil is 50:1 if my gas tank will hold 20L what percent of my mixture (gas & oil) is oil? and How much oil should i mix in m      Log On


   



Question 939742: for my outboard motor, the recommended ratio of gas to oil is 50:1
if my gas tank will hold 20L
what percent of my mixture (gas & oil) is oil? and How much oil should i mix in my gas tank?

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
50:1 ---> 50x L of gas, 1x L of oil

50x + 1x = 20

51x = 20

x = 20/51

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so you should mix 20/51 Liters of oil

20/51 is approximately 0.39215686

so you should have approximately 0.39215686 liters of oil
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