SOLUTION: Good evening I do need help with this problem. hope you could help me. You have a 4 pint mixture of paint that is made up of equal amounts of blue paint and red paint. to creat

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Good evening I do need help with this problem. hope you could help me. You have a 4 pint mixture of paint that is made up of equal amounts of blue paint and red paint. to creat      Log On


   



Question 877439: Good evening I do need help with this problem. hope you could help me.
You have a 4 pint mixture of paint that is made up of equal amounts of blue paint and red paint. to create a certain shade of purple, you need a paint mixture that is 65% blue.
a. let p represent the number of pints of blue paint that willbe in the new mixture. write an expression for the total number of pints of blue and red paint that will be in the new mixture
b. use your expressions from part (a) to write an equation that represents a paint mixture that is 60% blue.
Tnx

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The "4 pint mixture of paint that is made up of equal amounts of blue paint and red paint" contains
4pints%2F2=2pints of blue paint, and
4pints%2F2=2pints of red paint.

a.
If p represents the number of pints of blue paint that will be in the new mixture,
p-2 is the number of pints of blue paint that will be added to the "4 pint mixture of paint that is made up of equal amounts of blue paint and red paint."
2 is the number of pints of red paint that will be in the new mixture,
because that is how much was in the original mixture and no red paint will be added.
Then, p%2B2 is the total number of pints of paint (blue + red) that will be in the new mixture.
I do not know what the question asks for.
Is it asking for the number of pints of paint of each color? That would be 2pints of red and p pints of blue.
Is it asking for the total number of pints of paint? That would be p%2B2pints of paint.
Why were you given the 65% blue paint target for the final mixture?
Are you expected to use that 65% to calculate further and find the value of p in a mixture containing 65% blue paint and made as described?
If the new mixture is 65% blue paint, then
p%2F%28p%2B2%29=65%2F100 or p%2F%28p%2B2%29=0.65
p=0.65%28p%2B2%29-->p=0.65p%2B1.3-->p-0.65p=1.3-->0.35p=1.3-->p=1.3%2F0.35
That is p=26%2F7=3%265%2F7=about+3.41 , which means that you would add about or p%2F%28p%2B2%29=0.6