You can put this solution on YOUR website! How many milliliters of alcohol must be added to 200 milliliters of a 25% iodine solution to make a 10% iodine solution:
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Let x = amt of alcohol required;
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Think of Alcohol is a 0% iodine solution
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Final mixture amt = (x+200)
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Write a a % iodine equation:
.25(200) + 0(x) = .10(x+200)
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50 + 0 = .10x + 20
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50 - 20 = .10x
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30 = .10x
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x = 30/.10
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x = 300 ml of alcohol required to make a 10% iodine solution
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Check solution:
the total amt 200 + 300 = 500
.25(200) = .1(500)
50 = 50
