SOLUTION: The ratio of the number of yellow balls to the green balls in a bag was 4:7. When 6 green balls were removed and 3 more yellow balls were added to the bag, there were as many yello

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: The ratio of the number of yellow balls to the green balls in a bag was 4:7. When 6 green balls were removed and 3 more yellow balls were added to the bag, there were as many yello      Log On


   

Question 762578: The ratio of the number of yellow balls to the green balls in a bag was 4:7. When 6 green balls were removed and 3 more yellow balls were added to the bag, there were as many yellow balls as green balls. How many yellow balls and green balls were in the bag originally?
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
Ratio of yellow to green initially is 4:7.
Assume there were 4*x yellow balls, which means that there were 7*x green balls.
6 green balls removed. So number of green balls now is 7*x - 6
3 yellow balls added. So number of yellow balls now is 4*x + 3
After this change, it is given that the number of green balls and yellow balls are equal.
Hence 7%2Ax+-+6%29+=+%284%2Ax+%2B+3%29
Solve for x. Adding 6 to both sides, and subtracting 4*x from both sides,
3%2Ax+=+9 or x+=+3
Yellow balls = 4*x. Green = 7*x.
Hence number of yellow balls = highlight%2812%29 and number of green balls = highlight%2821%29
:)