SOLUTION: In 1998, Mark McGwire and Sammy Sosa hit a total of 136 home runs. McGwire hit 4 more home runs than Sosa. How many home runs did each player hit? Thank you!

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: In 1998, Mark McGwire and Sammy Sosa hit a total of 136 home runs. McGwire hit 4 more home runs than Sosa. How many home runs did each player hit? Thank you!      Log On


   

Question 733405:

In 1998, Mark McGwire and Sammy Sosa hit a total of 136 home runs. McGwire hit 4 more home runs than Sosa. How many home runs did each player hit?
Thank you!
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
S+M=136
M=S+4
S+(S+4)=136
2S=136-4
2S=132
S=132/2
S=66 HOME RUNS FOR SOSA.
M=66+4=70 HOME RUNS FOE McQUIRE.
PROOF:
66+70=136
136=136