SOLUTION: In 2006, Joan had to pay $1,580 in taxes. In 2007, she had to pay $1,738 in taxes. What was the percent of increase?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: In 2006, Joan had to pay $1,580 in taxes. In 2007, she had to pay $1,738 in taxes. What was the percent of increase?      Log On


   

Question 585930: In 2006, Joan had to pay $1,580 in taxes. In 2007, she had to pay $1,738 in taxes. What was the percent of increase?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Percent Increase = [(New - Old)/Old] * 100

Percent Increase = [(1738-1580)/1580] * 100

Percent Increase = [158/1580] * 100

Percent Increase = 0.1 * 100

Percent Increase = 10%
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