SOLUTION: Any help with the below question will be greatly appreciated. I can't seem to figure it out... A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Any help with the below question will be greatly appreciated. I can't seem to figure it out... A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is       Log On


   

Question 50390: Any help with the below question will be greatly appreciated. I can't seem to figure it out...
A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(t)=480(3/2)^t. Estimate the number of bacteria in the culture at noon the same day.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(t)=480(3/2)^t. Estimate the number of bacteria in the culture at noon the same day.
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From 8AM to noon is 4 hours, so t=4.
f(4)=480(3/2)^4
f(4)=480(5.0625)
f(4)= 2430 bacteria.
Cheers,
Stan H.