SOLUTION: Oil and gas are mixed in a ratio of 3:8. If the oil costs 73 cents per liter and the gas costs 35 cents per liter, how many full liters of the mixture can be made for $20?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Oil and gas are mixed in a ratio of 3:8. If the oil costs 73 cents per liter and the gas costs 35 cents per liter, how many full liters of the mixture can be made for $20?      Log On


   

Question 503674: Oil and gas are mixed in a ratio of 3:8. If the oil costs 73 cents per liter and the gas costs 35 cents per liter, how many full liters of the mixture can be made for $20?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = liters of oil
+%288%2F%283+%2B+8%29%29%2Aa+ = liters of gas
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+73a+%2B+35%2A%288%2F11%29%2Aa+=+2000+ (in cents)
Multiply both sides by 11
+803a+%2B+280a+=+22000+
+1083a+=+22000+
+a+=+20.314+
+%288%2F11%29%2Aa+=+14.774+
+20.314+%2B+14.774+=+35.088+
35.088 liters of the mixture can be made
for $20