SOLUTION: Melody Has $45,000 to invest and wishes to receive an annual income of $4290 from this money. She has chosen investments that pay 5%, 8%, and 12% simple interest. Melody wants to h

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Melody Has $45,000 to invest and wishes to receive an annual income of $4290 from this money. She has chosen investments that pay 5%, 8%, and 12% simple interest. Melody wants to h      Log On


   



Question 43727: Melody Has $45,000 to invest and wishes to receive an annual income of $4290 from this money. She has chosen investments that pay 5%, 8%, and 12% simple interest. Melody wants to have the amount invested at 12% to be double the amounted invested at 8%. How much should she invest at each rate.
Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Hello!
This can be solved with a system of 3 equations and 3 unknowns. Let's call X to the amount invested at 5%, Y to the amount invested at 8% and Z to the amount invested at 12%.
Since she has $45,000, we have:
X+%2B+Y+%2B+Z+=+45000
We also know that "Melody wants to have the amount invested at 12% to be double the amounted invested at 8%". Therefore,
Z+=+2Y
Finally, she "wishes to receive an annual income of $4290 from this money". Therefore, we get:
0.05X+%2B+0.08Y+%2B+0.12Z+=+4290
So we have the system:
system%28X+%2B+Y+%2B+Z+=+45000%2CZ+=+2Y%2C0.05X+%2B+0.08Y+%2B+0.12Z+=+4290%29

This system can be solved with any method you prefer (for example, by substitution). The solutions are:
X=9000
Y=12000
Z=24000
Therefore, she should invest $9,000 at 5%, $12,000 at 8% and $24,000 at 12%

I hope this helps!
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