SOLUTION: A chemist is mixing a 11% acidic solution with a 6% acidic solution to obtain 600 mL of an 8% acidic solution. How much of each must he have?

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Question 368329: A chemist is mixing a 11% acidic solution with a 6% acidic solution to obtain 600 mL of an 8% acidic solution. How much of each must he have?
Found 2 solutions by Fombitz, amoresroy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 11% acidic solution, B the amount of 6% acidic solution
1.A%2BB=600
11A%2B6B=8%28600%29
2.11A%2B6B=4800
Multiply eq. 1 by (-6) and add to eq. 2,
-6A-6B%2B11A%2B6B=-3600%2B4800
5A=1200
highlight%28A=240%29ml
Then from eq. 1,
240%2BB=600
highlight%28B=360%29ml

Answer by amoresroy(361) About Me  (Show Source):
You can put this solution on YOUR website!
A chemist is mixing a 11% acidic solution with a 6% acidic solution to obtain 600 mL of an 8% acidic solution. How much of each must he have?
Let x = the amount of 11% acidic solution
600-x = the amount of 6% acidic solution
.11x + .06(600-x) = .08(600)
.11x + 36 - .06x = 48
.05x = 12
x = 240
600 - x = 360
The chemist must have 240 mL of 11% acidic solution and 360 mL of 6% acidic solution.