SOLUTION: A flock of geese on a pond were being observed continuously.at 1:00 p.m, 1/5 of the geese flew away. At 2: p.m,1/8 of the geese that remained flew away, At 3:00 p.m, 3 times as man

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A flock of geese on a pond were being observed continuously.at 1:00 p.m, 1/5 of the geese flew away. At 2: p.m,1/8 of the geese that remained flew away, At 3:00 p.m, 3 times as man      Log On


   



Question 302611: A flock of geese on a pond were being observed continuously.at 1:00 p.m, 1/5 of the geese flew away. At 2: p.m,1/8 of the geese that remained flew away, At 3:00 p.m, 3 times as many geese as had flown away At 1:00 p.m .flew away, leaving 28 geese on the pond. At no other times did any geese arrive or fly away. How many geese were in the original flock
Answer by JBarnum(2146) About Me  (Show Source):
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A flock of geese on a pond were being observed continuously.at 1:00 p.m, 1/5 of the geese flew away. At 2: p.m,1/8 of the geese that remained flew away, At 3:00 p.m, 3 times as many geese as had flown away At 1:00 p.m .flew away, leaving 28 geese on the pond. At no other times did any geese arrive or fly away. How many geese were in the original flock


this gets a lil hectic but try to stay with me
F=total Flock of Geese
at 1pm (1/5)F flew away leaving (4/5)F
at 2pm (1/8)((4/5)F)=(4/40)F=(1/10)F so only (4/5)F-(1/10)F= (7/10)F remaining
at 3pm 3(1/5)F =(3/5)F which flew away from (7/10)F meaning (7/10)F-(3/5)F=(1/10)F remain.
if only 28 remain then 28=%281%2F10%29F
28%2810%29=%281%2F10%29F%2810%29
280=F
280 total geese in the flock