SOLUTION: A carpenter has a piece of lumber measuring 7 feet 6 and 3/4 inches long. How much must the carpenter saw off to be left with a piece 5 feet 11 5/16 inches long? (Note: Assume the

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A carpenter has a piece of lumber measuring 7 feet 6 and 3/4 inches long. How much must the carpenter saw off to be left with a piece 5 feet 11 5/16 inches long? (Note: Assume the       Log On


   

Question 19783: A carpenter has a piece of lumber measuring 7 feet 6 and 3/4 inches long. How much must the carpenter saw off to be left with a piece 5 feet 11 5/16 inches long? (Note: Assume the saw cut has no width)
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
total length: 7feet 6 and 3/4 inches
=7feet and (27/4)inches
=(7*12)+(27/4) inches
=84+(27/4)inches
=((4*84)+27)/4 inches
=(336+27)/4 inches
=363/4 inches


so total length of wood=363/4 inches


piece to be left with: 5 feet 11 5/16 inches
=(5*12)+(11 and 5/16)
=60+(11*16+5)/16
=60+(181/16)
=((16*60)+181)/16
=(960+181)/16
=1141/16 inches


now length to be cut off=total-piece
=(363/4)-(1141/16)
%28%284%2A363%29-1141%29%2F16
%281452-1141%29%2F16
311%2F16 inches


convert this to feet by dividing by 12
311%2F%2812%2A16%29
311%2F192
approx 1.6 feet
[1foot and (119/192)inches]


Hope this helps,
Prabhat