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Question 187282This question is from textbook
: Felipe jobs for 10 miles and then walks another 10 miles. He jobs 2 1/2 miles per hour faster than he walks, and the entire distance of 20 miles takes 6 hours. find the rate at which he walks and the rate at which he jogs.
This question is from textbook
Found 3 solutions by josmiceli, MathTherapy, josgarithmetic:
Answer by josmiceli(19441)   (Show Source):
Answer by MathTherapy(10806)  (Show Source):
You can put this solution on YOUR website!
Felipe jobs for 10 miles and then walks another 10 miles. He jobs 2 1/2 miles per hour faster than he walks, and
the entire distance of 20 miles takes 6 hours. find the rate at which he walks and the rate at which he jogs.
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The other person's solution is rather lengthy, and in this author's opinion, a few UNNECESSARY variables were introduced.
Furthermore, he suggests using the quadratic formula to solve his final equation, which can be easily FACTORIZED.
Let the speed at which he walks, be S
Then, his jogging speed =  , or S + 2.5
Time taken to walk 10 miles:  , and time taken to jog 10 miles = 
As he takes 6 hours to walk and jog 20 miles, we get the following
TOTAL-TIME equation: 
10(S + 2.5) + 10S = 6S(S + 2.5) ----- Multiplying by LCD, S(S + 2.5)
(2S - 5)(3S + 5) = 0
2S - 5 = 0 or 3S + 5 = 0 ---- Setting FACTORS equal to 0
2S = 5 or 3S = - 5 (IGNORE)
Walking speed, or S =  = 2.5 mph
Jogging speed: S + 2.5 = 2.5 + 2.5 = 5 mph
You can do the CHECK!!
Answer by josgarithmetic(39792)  (Show Source):
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