SOLUTION: Hi the question is this Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 93 miles in the same time dana travels 84 miles. Chucks rate of travel is 3mph mor

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Question 138985: Hi the question is this
Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 93 miles in the same time dana travels 84 miles. Chucks rate of travel is 3mph more than Danas and they travel the same length of time at what speed does Chuck travel?
Thanks a lot
C
Found 2 solutions by checkley77, solver91311:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
93/(x+3)=84/x
84(x+3)=93x
84x+252=93x
84x-93x=-252
-9x=-252
x=-252/-9
x=28 mph for Dana's speed.
28+3=31 mph for Chuck's speed.
proof:
93/31=84/28
3=3

Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!
The basic formula is , distance equals rate times time.

Let Chuck's rate be and Dana's rate be .

Chuck traveled 93 miles at a rate of for some time

Dana traveled 84 miles at a rate of for the SAME time

If we rearrange the basic formula so that it is solved for time we get

So, Chuck's trip took hours, and Dana's trip took hours. But the time was the same for both trips, so we can say:

We are also told that Chuck's rate is 3 mph greater than Dana's, so , and we can substitute this fact into the last equation, thus:

Now all you have to do is solve this equation for to get Chuck's speed. HINT: Cross multiply this proportion and then collect like terms