SOLUTION: Sarah had some money in the piggy bank. On Monday, she took out 2/5 of the money to buy a present. She had $78 left and she put it back into the piggy bank. On Tuesday, she took ou

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Sarah had some money in the piggy bank. On Monday, she took out 2/5 of the money to buy a present. She had $78 left and she put it back into the piggy bank. On Tuesday, she took ou      Log On


   



Question 1202330: Sarah had some money in the piggy bank. On Monday, she took out 2/5 of the money to buy a present. She had $78 left and she put it back into the piggy bank. On Tuesday, she took out 3/8 of the money to buy some story books. She had $28.80 left and she put it back into the piggy bank. After that, she found that there was $246.30 in the piggy bank. How much money did she have in the piggy bank at first?
Found 2 solutions by math_tutor2020, MathTherapy:
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

Answer: $450

Work Shown:
x = starting amount

(2/5)x = amount she withdraws on Monday
x - (2/5)x = (3/5)x = amount left in the piggy bank, before the $78 is added
(3/5)x + 78 = amount after the $78 is added

(3/5)x + 78 = starting amount for Tuesday
(3/8)*((3/5)x + 78) = amount withdrawn on Tuesday
(5/8)*((3/5)x + 78) = amount in the piggy bank before the $28.80 is added
(5/8)*((3/5)x + 78)+28.80 = amount in the piggy bank after the $28.80 is added

That final expression is set equal to 246.30 which is the amount she has in the piggy bank after all is said and done.

(5/8)*((3/5)x + 78)+28.80 = 246.30
(5/8)*(3/5)x + (5/8)*78+28.80 = 246.30
(3/8)x + 48.75 + 28.80 = 246.30
(3/8)x + 77.55 = 246.30
(3/8)x = 246.30 - 77.55
(3/8)x = 168.75
x = 168.75*(8/3)
x = 450


Check:
Start with $450
(2/5)*450 = 180 dollars withdrawn on Monday
450-180 = 270 dollars remain in the piggy bank
270+78 = 348 dollars at the end of Monday
Then,
(3/8)*348 = 130.50 dollars withdrawn on Tuesday
348-130.50 = 217.50 dollars remain
217.50+28.80 = 246.30 dollars in the piggy bank at the end of Tuesday
We have fully confirmed the answer is correct.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Sarah had some money in the piggy bank. On Monday, she took out 2/5 of the money to buy a present. She had $78 left and she put it back into the piggy bank. On Tuesday, she took out 3/8 of the money to buy some story books. She had $28.80 left and she put it back into the piggy bank. After that, she found that there was $246.30 in the piggy bank. How much money did she have in the piggy bank at first?

Let initial amount in piggy bank be A
After taking out matrix%281%2C3%2C+%282%2F5%29A%2C+or%2C+2A%2F5%29, she had matrix%281%2C3%2C+%281+-+2A%2F5%29%2C+or%2C+3A%2F5%29 remaining
Since the remainder from the 2A%2F5, was $78, then after placing the $78 back, there was 3A%2F5+%2B+78 in the piggy bank

On Tuesday, 3%2F8 of remainder was taken out leaving 5%2F8 of remainder or matrix%281%2C5%2C+5%2F8%2C+of%2C+%283A%2F5+%2B+78%29%2C+or%2C+3A%2F8+%2B+195%2F4%29

     After placing the $28.80 back into the piggy bank, she then had 3A%2F8+%2B+195%2F4+%2B+28.8

  Since the final amount in the piggy bank was $246.30, we then get:  
                                                                                 3A = 1,740 - 390 -------- Multiplying by LCD, 8
                                                                                 3A = 1,350
                                                Initial amount in piggy bank, or