SOLUTION: Let A, B, and C be three of the most popular television shows of all time. The total number of episodes of these three shows is 581. There are 26 more episodes of A than C, and the
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: Let A, B, and C be three of the most popular television shows of all time. The total number of episodes of these three shows is 581. There are 26 more episodes of A than C, and the
Log On
Question 1171124: Let A, B, and C be three of the most popular television shows of all time. The total number of episodes of these three shows is 581. There are 26 more episodes of A than C, and the difference between the number of episodes of B and C is 12. Find the number of episodes of each show. Answer by ikleyn(52824) (Show Source):
Let x = the number of C.
Then the number of A is x+26
and the number of B is x+12, according to the condition.
You have then this equation for the total
x + (x+26) + (x+12) = 581
which gives
3x = 581 - 26 - 12 = 543, x = 543/3 = 181.
ANSWER. C = 181; A = 181 + 26 = 207 and B = 181 + 12 = 193.
