SOLUTION: A 2-cup mixture consists of 1/3 flour and 2/3
cornmeal. If 1 cup of flour is added to make a 3- cup mixture, approximately what percent of the 3-cup mixture is flour?
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: A 2-cup mixture consists of 1/3 flour and 2/3
cornmeal. If 1 cup of flour is added to make a 3- cup mixture, approximately what percent of the 3-cup mixture is flour?
Log On
Question 1092992: A 2-cup mixture consists of 1/3 flour and 2/3
cornmeal. If 1 cup of flour is added to make a 3- cup mixture, approximately what percent of the 3-cup mixture is flour? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39621) (Show Source):
You can put this solution on YOUR website! ---------------------------------------------------
A 2-cup mixture consists of 1/3 flour and 2/3
cornmeal
---------------------------------------------------
Just that much means the recipe initially was expected to be:
TWO-CUP MIXTURE
, cup of flour
, cup of cornmeal
, cup of other ingredients
---------------------------------------------------------------
If 1 cup of flour is added to make a 3- cup mixture, approximately what percent of the 3-cup mixture is flour?
---------------------------------------------------------------
Now, total flour is
and
total amount of cups of mixture became 3, as given.
What percent as flour?
of the 2-cup mixture is exactly cup of floor. <<<---=== A 2-cup mixture consists of 1/3 flour and 2/3 cornmeal.
After adding 1 cup of floor we have = cup of floor.
Now, the ratio : 3 = = 0.5555 = 55.55%.
Answer. Approximately what percent of the 3-cup mixture is flour? - 55.55%. Approximately.
============================
Dear "students" !
Today is a special day.
Today I solved 16 problems for you and got back 0 (zero, ZERO) "thanks" from you.
It is the absolute record !
It is just out of limits of my understanding !
I never saw it before !
Thank you very much and wish you to think: WHO ARE YOU . . .