SOLUTION: The length of the sides of two squares are 4cm and 2cm. Find, in its simplest form, the ratio of their (i) perimeters (ii)areas

Question 1086758: The length of the sides of two squares are 4cm and 2cm. Find, in its simplest form, the ratio of their (i) perimeters (ii)areas
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Perimeter is directly proportional so if the side doubles the perimeter doubles
The perimeter =4s, 8 cm for the first square and 16 for the second.
The area is proportional to the square of the side, so the area is 4 times as large for the second.
area of the first=s^2=4 cm^2; area of second is 16 cm^2, 4 times as much.
Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!
The length of the sides of two squares are 4cm and 2cm. Find, in its simplest form, the ratio of their (i) perimeters (ii)areas

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