SOLUTION: At noon, a ship leaves a harbor and sails south at 10 knots. Two hours later, a second ship leaves the harbor and sails east at 15 knots. When will the ships be 100 nautical miles

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: At noon, a ship leaves a harbor and sails south at 10 knots. Two hours later, a second ship leaves the harbor and sails east at 15 knots. When will the ships be 100 nautical miles       Log On


   

Question 1009301: At noon, a ship leaves a harbor and sails south at 10 knots. Two hours later, a second ship leaves the harbor and sails east at 15 knots. When will the ships be 100 nautical miles apart? Round to the nearest minute.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Let theta be an angle in quadrant 2 such that sec theta=-5/4. Find the exact values of cot theta and sin theta.?
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Note:: x is negative and y is positive in QII.
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By definition, sec(t) = r/x
So, r = 5 and x = -4.
Then y = sqrt[5^2-4^2] = sqrt(25-16) = sqrt(9) = 3
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Answers::
cot(t) = x/y = -4/3
sin(t) = y/r = 3/5
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Cheers,
Stan H.
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