I won't do your for you. I'll do one exactly like it.
ABCD is rhombus. If ∠BAC = 36°, find ∠ADB and ∠ ABC.
∠ DAC = 36° because the diagonals of a rhombus bisect each other.
AC ⊥ BC because the diagonals of a rhombus are perpendicular.
ΔAED is a right triangle because two sides are perpendicular.
∠ ADB = 54° because the two angles of a right triangle are complementary.
AB ≅ AD Sides of a rhombus are congruent
ΔABD is isosceles 2 sides congruent
∠ ABD = 54° Base angles of isosceles triangle are congruent
AB ≅ BC Sides of a rhombus are congruent
ΔABC is isosceles 2 sides congruent
∠ BCA = 36° Base angles of isosceles triangle are congruent
∠BAC + ∠BCA + ∠ABC = 180° Property of all triangles
∠ABC = 180° - ∠BAC - ∠BCA
∠ABC = 180° - 36° - 36° = 108°
Now do yours the same way.
Edwin