SOLUTION: (-35y^3u^2+20y^2u)/(-4y^3u^2)
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Question 997855
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(-35y^3u^2+20y^2u)/(-4y^3u^2)
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It is costly, MathTherapy
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Answer by
It is costly(175)
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Answer by
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(-35y^3u^2+20y^2u)/(-4y^3u^2)
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